document.write( "Question 1137589: Eliminate the parameter.
\n" ); document.write( "x = t2 + 3, y = t2 - 2 (2 points)\r
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\n" ); document.write( "y = x + 5, x ≥ 3
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\n" ); document.write( "y = x2 - 5, x ≥3
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\n" ); document.write( "y = x - 5, x ≥ 3
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\n" ); document.write( "y = x2 + 5, x ≥3
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Algebra.Com's Answer #755526 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "NOTE: Use \"^\" (shift-6) to denote exponentiation....

\n" ); document.write( "Given: x = t^2 + 3, y = t^2 - 2

\n" ); document.write( "Rearranged: t^2 = x-3; t^2 = y+2 --> x-3 = y+2 --> y = x-5

\n" ); document.write( "Then, with the given definition x = t^2+3, we know the minimum value of x is 3; then the complete answer is

\n" ); document.write( "y = x-5; x >= 3
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