document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=103870>Question 103870</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the distance between (-3,-2) and (1,4) \r<BR>\n" );
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document.write( "a 27\r<BR>\n" );
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document.write( "b 2 square root 5\r<BR>\n" );
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document.write( "c 2 square root 13\r<BR>\n" );
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document.write( "d square root 10  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #75548 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=75548\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -3-1=-4<BR>\n" );
document.write( "-2-4=-6<BR>\n" );
document.write( "(-4)^2+(-6)^2=16+36=52<BR>\n" );
document.write( "sqrt(52)=2sqrt(13)<BR>\n" );
document.write( "Ed </SPAN>\n" );
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