document.write( "Question 1137617: What is the probability of drawing three queens from a standard deck of cards, given that the first card drawn was a queen? Assume that the cards are not replaced.
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Algebra.Com's Answer #755471 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "The first card drawn was a queen
\n" ); document.write( "So we have 52-1 = 51 cards left, 4-1 = 3 of which are queens.\r
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\n" ); document.write( "\n" ); document.write( "The probability of a queen on the second draw is 3/51 since there are 3 cards we want out of 51 total. \r
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\n" ); document.write( "\n" ); document.write( "Then the probability of another queen after that is 2/50 since there are 2 queens left and 50 cards total (3-1 = 2; 51-1 = 50)\r
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\n" ); document.write( "\n" ); document.write( "Multiplying those fractions out gives us
\n" ); document.write( "(3/51)*(2/50) = (3*2)/(51*50) = 6/2550 = 1/425\r
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\n" ); document.write( "\n" ); document.write( "The answer as a fraction is 1/425
\n" ); document.write( "The answer in decimal form is roughly 0.00235
\n" ); document.write( "This converts to 0.235%
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