document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1137574>Question 1137574</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given f(x)=(x+8)^2-3 , determine the equation of the inverse. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #755452 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=755452\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you would find the reverse as follows:\r<BR>\n" );
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document.write( "startwith y = (x + 8) ^ 2 - 3\r<BR>\n" );
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document.write( "replace y with x and x with y to get x = (y + 8) ^ 2 - 3\r<BR>\n" );
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document.write( "add 3 to both sides of the equation to get x + 3 = (y + 8) ^ 2\r<BR>\n" );
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document.write( "take the square root of both sides of the equation to get plus or minus sqrt(x + 3) = y + 8\r<BR>\n" );
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document.write( "subtract 8 from both sides of the equation to get -8 plus or minus sqrt(x + 3) = y\r<BR>\n" );
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document.write( "your inverse equation is y = -8 plus or minus sqrt(x + 3)\r<BR>\n" );
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document.write( "if that inverse equation is correct, then (x,y) in the regular equation will be equal to (y,x) in the inverse equation.\r<BR>\n" );
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document.write( "this can be seen to be true in the following graph.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2019/032821.jpg\" alt=\"$$$\" >\r<BR>\n" );
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document.write( "what is shown is that the original equation and the inverse equation are reflected about the line y = x as they should be.\r<BR>\n" );
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document.write( "the points of each are equidistant from the line y = x, which is shown by drawing the line y = -x + 20 that is vertical to the line y = x.\r<BR>\n" );
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document.write( "the points equidistant from the line y = x will be on the line y = -x + 20 as shown.\r<BR>\n" );
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document.write( "the point (-2.91, 22.91) and the point (22.91, -2.91) are equidistant from the line y = x.\r<BR>\n" );
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document.write( "the point (-14.09, 34.09) and the point (34.09, -14.09) are equidistant from the line y = x.\r<BR>\n" );
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document.write( "that confirms that the regular equation and the inverse equation are indeed inverse equations of each other.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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