document.write( "Question 103850: How many pounds of seed worth $0.60 a pound must be mixed with 300 pounds of seed worth $0.35 a pound to produce a mixture worth $0.50 per pound?\r
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document.write( "Thanks so much!!! \n" );
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Algebra.Com's Answer #75545 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! How many pounds of seed worth $0.60 a pound must be mixed with 300 pounds of seed worth $0.35 a pound to produce a mixture worth $0.50 per pound? \n" ); document.write( ": \n" ); document.write( "Let x = amt of .60/lb seed \n" ); document.write( ": \n" ); document.write( ".60x + .35(300) = .50(x + 300) \n" ); document.write( ": \n" ); document.write( ".60x + 105 = .50x + 150 \n" ); document.write( ": \n" ); document.write( ".60x - .50x = 150 - 105 \n" ); document.write( ": \n" ); document.write( ".1x = 45 \n" ); document.write( ": \n" ); document.write( "x = 45/.1 \n" ); document.write( ": \n" ); document.write( "x = 450 lb of .60/lb seed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution: \n" ); document.write( ".6(450) + .35(300) = .50(450 + 300) \n" ); document.write( " 270 + 105 = .5(750) \n" ); document.write( " 375 = 375 \n" ); document.write( " |