Algebra.Com's Answer #755448 by ikleyn(53938)  You can put this solution on YOUR website! . \n" );
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document.write( " >= \r\n" );
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document.write( "has the domain x =/= -2 and x =/= 2 and is equivalent to (moving the right part to the left)\r\n" );
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document.write( " - >= 0\r\n" );
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document.write( "Write with the common denominator\r\n" );
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document.write( " >= 0.\r\n" );
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document.write( "Simplify step by step\r\n" );
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document.write( " >= 0,\r\n" );
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document.write( " >= 0,\r\n" );
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document.write( " >= 0. (1)\r\n" );
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document.write( "Simplifying is completed. Next we start analyzing.\r\n" );
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document.write( "The critical points, where the rational function (1) changes its sign, are the points -2, 0, 2 and 4.\r\n" );
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document.write( "They divide the number line in 5 intervals.\r\n" );
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document.write( "1) Interval ( , ). \r\n" );
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document.write( " All four separate factors are negative, hence, the function is POSITIVE.\r\n" );
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document.write( " Thus this interval IS the part of the solution.\r\n" );
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document.write( "2) Interval ( , ). \r\n" );
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document.write( " One factor, (x+2) is positive; the other 3 factors are negative; hence, the function is NEGATIVE.\r\n" );
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document.write( " Thus this interval is NOT the part of the solution.\r\n" );
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document.write( "3) Interval [ , ). \r\n" );
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document.write( " Two factors, (x+2) and x, are positive; the other 2 factors are negative; hence, the function is POSITIVE.\r\n" );
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document.write( " Thus this interval IS the part of the solution.\r\n" );
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document.write( "Moving forward along the number line interval after interval, and analyzing by the similar way, you get the \r\n" );
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document.write( "ANSWER. The solution is the union of the following intervals:\r\n" );
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document.write( " ( , ) U [ , ) U [ , ).\r\n" );
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document.write( "Completed, explained and solved.\r \n" );
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document.write( "Do you understand now why the forum requires one and only one problem per post ?\r \n" );
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document.write( "Because otherwise you will get a mess.\r \n" );
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