document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1137523>Question 1137523</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the series in summation notation and find the sum\r<BR>\n" );
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document.write( "6+2+(2/3)+(2/9)+...+(2/729) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #755405 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=755405\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is 6*(1/3)^n, where n runs from 0 to 6. Sum n=0 to 6 of 6*(1/3)^n<BR>\n" );
document.write( "the terms are 6<BR>\n" );
document.write( "2<BR>\n" );
document.write( "2/3<BR>\n" );
document.write( "2/9<BR>\n" );
document.write( "2/27<BR>\n" );
document.write( "2/81<BR>\n" );
document.write( "2/243<BR>\n" );
document.write( "2/729\r<BR>\n" );
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document.write( "sum of 7 =a(1-(1/3)^8)/(1-(1/3))<BR>\n" );
document.write( "This is 6*(1-1/6561)/(2/3)<BR>\n" );
document.write( "This is 9(1-1/6561)<BR>\n" );
document.write( "or 9-9/6561<BR>\n" );
document.write( "This is 9-3/2187 which is the same as 8+2184/2187\r<BR>\n" );
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document.write( "8+2/3+...<BR>\n" );
document.write( "8+(1458/2187)+(486/2187)+(162/2187)+(54/2187)+(18/2187)+(6/2187)<BR>\n" );
document.write( "8+(2184/2187) ANSWER\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );