document.write( "Question 1137460: What will be the time (in seconds) taken by a small stone to reach the surface of the Earth if it is dropped from a height R/4 where R = 6 400 km, Mass of Earth =6 x 10^24 kg. \n" ); document.write( "
Algebra.Com's Answer #755396 by rothauserc(4718) You can put this solution on YOUR website! The small stone is at rest when it is dropped from a height of 6400/4 = 1600 km \n" ); document.write( ": \n" ); document.write( "Note The acceleration of gravity will be less for the stone at height 1600 km than if the stone is near the surface of the earth \n" ); document.write( ": \n" ); document.write( "We know that \n" ); document.write( ": \n" ); document.write( "F = ma = GmM/r^2, where M is the mass of the earth, G is the gravitational constant, m is the mass of the stone, M is the mass of the Earth and r is distance from the center of the earth to the stone \n" ); document.write( ": \n" ); document.write( "The distance from the center of the earth to its surface is 6400 km, therefore r is 6400 + 1600 = 8000 km \n" ); document.write( ": \n" ); document.write( "a = ( 6.677 x 10^-11 m^3 kg^-1 s^-2) * (5.972 x 10^24 kg) / (8000000)^2 \n" ); document.write( ": \n" ); document.write( "a = (39.875 x 10^13) / (6.4 x 10^13) = 6.23 m/sec^2 \n" ); document.write( ": \n" ); document.write( "distance = v(0)t +(1/2)at^2, where v(0) = 0, distance = 8000000 m \n" ); document.write( ": \n" ); document.write( "Here, problems arise, notably the acceleration of gravity will increase as the object approaches the surface of the earth, air friction will increase as well \n" ); document.write( ": \n" ); document.write( "What assumptions has your teacher given you about this problem? \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |