document.write( "Question 1137495: The volume V of an ideal gas varies directly with the temperature T and inversely with the pressure P. A cylinder contains oxygen at a temperature of 310 degrees K and a pressure of 18 atmospheres in a volume of 120 liters. What is the pressure if the volume is decreased to 100 liters and the temperature is increased to 320 degrees K? \n" ); document.write( "
Algebra.Com's Answer #755371 by ikleyn(52832)\"\" \"About 
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document.write( "From the condition, you have this general formula\r\n" );
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document.write( "    V = \"k%2A%28T%2FP%29\",\r\n" );
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document.write( "where \" k \" is  a constant value.\r\n" );
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document.write( "From the condition, you also have these two expressions for two states of the gas:\r\n" );
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document.write( "    120 = \"k%2A%28310%2F18%29\"    (1)\r\n" );
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document.write( "and\r\n" );
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document.write( "    100 = \"k%2A%28320%2FP%29\",    (2)\r\n" );
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document.write( "where P is the unknown pressure under the question.\r\n" );
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document.write( "Divide expression (1) by expression (2) (both sides).  You will get\r\n" );
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document.write( "    \"120%2F100\" = \"%28%28310%2F18%29%29%2F%28%28320%2FP%29%29\",   or\r\n" );
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document.write( "     1.2 = \"%28310%2AP%29%2F%2818%2A320%29\".\r\n" );
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document.write( "which implies\r\n" );
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document.write( "     P = \"%281.2%2A18%2A320%29%2F310\" = 22.297   atmospheres.    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "It is the shortest way to solve such problems.\r
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\n" ); document.write( "\n" ); document.write( "The other approach with calculating the constant value \" k \" forces you to make unnecessary calculations on the way to the answer.\r
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