document.write( "Question 1137432: A cone frustum is inscribed in a sphere of radius 13. If one of the bases of the frustum is a great circle of the sphere, and the other base has radius 12, what is the slant height. \n" ); document.write( "
Algebra.Com's Answer #755328 by ikleyn(52786)\"\" \"About 
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document.write( "1.  The height of the frustum is equal to the distance from the center of the sphere to the smaller base of the frustum\r\n" );
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document.write( "    h = \"sqrt%2813%5E2-12%5E2%29\" = \"sqrt%2825%29\" = 5 units.\r\n" );
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document.write( "2.  Hence, the slant height is equal to\r\n" );
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document.write( "    H = \"sqrt%28h%5E2+%2B+%28R-r%29%5E2%29\" = \"sqrt%285%5E2+%2B+%2813-12%29%5E2%29\" = \"sqrt%2825+%2B+1%29\" = \"sqrt%2826%29\".    ANSWER\r\n" );
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