document.write( "Question 1137449: do the diagonals of ABCD bisect each other?\r
\n" ); document.write( "\n" ); document.write( "A(-1,-7), B(-3,-5), C(-2,2), D(0,0)\r
\n" ); document.write( "\n" ); document.write( "There is nothing in my notes on this and I emailed my teacher asking for help. So any help is appreciated. Thanks!
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Algebra.Com's Answer #755325 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
If a quadrilateral is a \"parallelogram\", then the diagonals \"bisect\" each other. \r
\n" ); document.write( "\n" ); document.write( "If \"AB\" || \"CD\", \"BC\" || \"AD\", it’s a parallelogram. Parallel lines have \"same\"\"+slope\".\r
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\n" ); document.write( "\n" ); document.write( "So, if slope of \"AB\" = to slope of \"CD\", and slope of \"BC\" = to slope of \"+AD+\"then it’s a \"parallelogram\".\r
\n" ); document.write( "\n" ); document.write( "slope of \"AB\" is \"%28-5-%28-7%29%29%2F%28-3-%28-1%29%29=%28-5%2B7%29%2F%28-3%2B1%29=2%2F-2=-1\"
\n" ); document.write( "slope of \"CD\" is \"%280-2%29%2F%280-%28-2%29%29=-2%2F2=-1\"\r
\n" ); document.write( "\n" ); document.write( "=>slope of \"AB+=+CD\" is same\r
\n" ); document.write( "\n" ); document.write( "slope of \"BC+\"is\"+%282-%28-5%29%29%2F%28-2-%28-3%29%29=%282%2B5%29%2F%28-2%2B3%29=7%2F1=7\"
\n" ); document.write( "slope of \"AD\" is \"%280-%28-7%29%29%2F%280-%28-1%29%29=7%2F1=7\"\r
\n" ); document.write( "\n" ); document.write( "=>slope of and \"BC+=+AD\" is same\r
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\n" ); document.write( "\n" ); document.write( "hence, \"AB\" || \"CD\", \"BC\" || \"AD\",=> \"ABCD\" is a \"parallelogram\"\r
\n" ); document.write( "\n" ); document.write( "that is enough to prove the diagonals of \"ABCD\" bisect each other\r
\n" ); document.write( "\n" ); document.write( "you can also do it this way:\r
\n" ); document.write( "\n" ); document.write( "find midpoint \"M\" of diagonals \"AC\" and \"BD\", prove that distances \"AM=MC\" and \"BM=MD\"\r
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Solved by pluggable solver: Finding midpoint of 2 points
We use the midpoint formula to solve. The x coordinate is \"%28x%5B1%5D%2Bx%5B2%5D%29%2F2\" Plug in the values,\r
\n" ); document.write( "\n" ); document.write( "\"%28-1%2B-2%29%2F2\" \"-3%2F2\" The x coordinate is -1.5. Now for the y.\r
\n" ); document.write( "\n" ); document.write( "\"%28-7%2B2%29%2F2\" \"-5%2F2\" The y coordinate is -2.5. The midpoint is at point (-1.5,-2.5). \r
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\n" ); document.write( "\n" ); document.write( "midpoint of diagonal AC:is at point (-1.5,-2.5)\r
\n" ); document.write( "\n" ); document.write( "The distance \"AM=+4.5\"
\n" ); document.write( "The distance \"MC=+4.5\"\r
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Solved by pluggable solver: Finding midpoint of 2 points
We use the midpoint formula to solve. The x coordinate is \"%28x%5B1%5D%2Bx%5B2%5D%29%2F2\" Plug in the values,\r
\n" ); document.write( "\n" ); document.write( "\"%280%2B-3%29%2F2\" \"-3%2F2\" The x coordinate is -1.5. Now for the y.\r
\n" ); document.write( "\n" ); document.write( "\"%280%2B-5%29%2F2\" \"-5%2F2\" The y coordinate is -2.5. The midpoint is at point (-1.5,-2.5). \r
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\n" ); document.write( "\n" ); document.write( "midpoint of diagonal BD: is at point (-1.5,-2.5)\r
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\n" ); document.write( "\n" ); document.write( "The distance \"BM=++2.9\"
\n" ); document.write( "The distance \"MD=++2.9\"\r
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\n" ); document.write( "\n" ); document.write( "check the graph:\r
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\n" ); document.write( "\n" ); document.write( "so, answer is: the diagonals of \"ABCD+\"bisect each other\r
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