document.write( "Question 1137426: Area of original rectangle is 12 x²+11x-5f t² Area is changed by decreasing the length by 2ft and increasing the width by 4ft. Find the new area
\n" ); document.write( "*remember the length is always the longer side.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #755301 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "Area of original rectangle is \r
\n" ); document.write( "\n" ); document.write( "\"12x%5E2%2B11x-5\"....factor completely to find expressions for length and width\r
\n" ); document.write( "\n" ); document.write( "\"12x%5E2-3x%2B15x-5\"\r
\n" ); document.write( "\n" ); document.write( "\"%2812x%5E2-4x%29%2B%2815x-5%29\"\r
\n" ); document.write( "\n" ); document.write( "\"4x%283x-1%29%2B5%28x-1%29\"\r
\n" ); document.write( "\n" ); document.write( "\"%283x+-+1%29+%284+x+%2B+5%29\"\r
\n" ); document.write( "\n" ); document.write( "let
\n" ); document.write( "\"%283x+-+1%29\"=> be the length
\n" ); document.write( "\"%284+x+%2B+5%29\"=> be the width\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Area is changed by:
\n" ); document.write( "
\n" ); document.write( "\"decreasing\" the length by \"2\" ft =>\"%283x+-+1-2%29\"=>\"%283x+-+3%29\"\r
\n" ); document.write( "\n" ); document.write( "and \"increasing\" the width by \"4\" ft=>\"%284+x+%2B+5%2B4%29\"=>\"%284+x+%2B+9%29\"\r
\n" ); document.write( "\n" ); document.write( " the new area is:\r
\n" ); document.write( "\n" ); document.write( "\"%283x+-+3%29%284+x+%2B+9%29\".....expand\r
\n" ); document.write( "\n" ); document.write( "\"12+x%5E2+%2B+15+x+-+27\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );