document.write( "Question 1137421: there are 37 chocolates in a box,all identically shaped. There are 9 filled with nuts, 13 filled with caramel, and 15 are solid chocolate. You randomly select one piece, eat it, and then select a second piece. Find the probability of selecting 2 solid chocolates in a row \n" ); document.write( "
Algebra.Com's Answer #755297 by Edwin McCravy(20054)\"\" \"About 
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document.write( "Two ways:\r\n" );
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document.write( "First way:\r\n" );
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document.write( "The probability of selecting the first piece as a solid chocolate is 15 out of 37, or 15/37.\r\n" );
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document.write( "Then 15/37ths of the time you select a solid chocolate and eat it.\r\n" );
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document.write( "Now there are only 36 pieces including only 14 solid chocolates.\r\n" );
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document.write( "So 14/36ths (which reduces to 7/18ths) of those 15/37ths of the time, you'll select a second solid chocolate.\r\n" );
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document.write( "So 7/18ths of 15/37ths is (7/18)(15/37) = 105/666 = 35/222ths, so the\r\n" );
document.write( "probability is 35/222.\r\n" );
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document.write( "Second way:\r\n" );
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document.write( "(15 solids choose 2)/(37 pieces choose 2) = (15C2)/(37C2) = 105/666 = 35/222.\r\n" );
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document.write( "Edwin
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