document.write( "Question 103808: The weights of certain machine componets are normally distrubited with a mean of 8.75g and a standard deviation of 0.07g. Find the two weights that seperate the top 3% and the bottom 3%. These weights could serve as limit used to identify which componets should be rejected. \n" ); document.write( "
Algebra.Com's Answer #75529 by stanbon(75887)\"\" \"About 
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The weights of certain machine componets are normally distrubited with a mean of 8.75g and a standard deviation of 0.07g. Find the two weights that seperate the top 3% and the bottom 3%. These weights could serve as limit used to identify which componets should be rejected.
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\n" ); document.write( "Use your z-chart or your calculator to find the \"z\" value that separates the top 3% and the bottom 3%.
\n" ); document.write( "That value is z= 1.88 and z=-1.88
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\n" ); document.write( "Then find the weights that correspond to those z values:
\n" ); document.write( "Let the weight be \"x\":
\n" ); document.write( "z = (x-mu)/sigma
\n" ); document.write( "1.88 = (x-8.75)/0.07
\n" ); document.write( "x= 0.07*1.88+8.75
\n" ); document.write( "x = 8.8816 lbs is the weight that separates the top 3%.
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\n" ); document.write( "-1.88 = (x-mu)/sigma
\n" ); document.write( "x = 0.07(-1.88)+8.75
\n" ); document.write( "x = 8.6184 lbs is the weight that separates the bottom 3%
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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