document.write( "Question 1137376: I need help finding the value of the trig functions\r
\n" ); document.write( "\n" ); document.write( "1. Use special right triangles to state the value of the 6 trig functions for 30 degrees, 45 degrees and 60 degrees
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Algebra.Com's Answer #755285 by greenestamps(13206)\"\" \"About 
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\n" ); document.write( "As you begin studying trigonometry, you need to be able to quickly find the values of the trig functions for these special angles. Rote memorization is not a particularly good method; having a picture in your mind of where those angles comes from is a much more reliable method.

\n" ); document.write( "For the 45 degree angle, think of the diagonal of a square. If the side lengths of the square are 1, then the diagonal (by the Pythagorean Theorem) is sqrt(2). Then

\n" ); document.write( "sin(45) = cos(45) = \"1%2Fsqrt%282%29+=+sqrt%282%29%2F2\"
\n" ); document.write( "tan(45) = \"sin%2845%29%2Fcos%2845%29+=+1\"
\n" ); document.write( "cot(45) = \"1%2Ftan%2845%29+=+1%2F1+=+1\"
\n" ); document.write( "sec(45) = \"1%2Fcos%2845%29+=+sqrt%282%29\"
\n" ); document.write( "csc(45) = \"1%2Fsin%2845%29+=+sqrt%282%29\"

\n" ); document.write( "For the 30 and 60 degree angles, think of an equilateral triangle cut in half; that forms two 30-60-90 right triangles. If the side length of the triangle is 1, then the short side of each 30-60-90 right triangle is 1/2 (half the length of a side of the triangle). Then the Pythagorean Theorem give us the length of the long leg of each 30-60-90 right triangle as sqrt(3)/2. Then

\n" ); document.write( "sin(30) = cos(60) = \"%281%2F2%29%2F1+=+1%2F2\"
\n" ); document.write( "cos(30) = sin(60) = \"%28sqrt%283%29%2F2%29%2F1+=+sqrt%283%29%2F2\"
\n" ); document.write( "tan(30) = cot(60) = \"%281%2F2%29%2F%28sqrt%283%29%2F2%29+=+1%2Fsqrt%283%29+=+sqrt%283%29%2F3\"
\n" ); document.write( "csc(30) = sec(60) = \"1%2F%281%2F2%29+=+2\"
\n" ); document.write( "csc(60) = sec(30) = \"1%2F%28sqrt%283%29%2F2%29+=+2%2Fsqrt%283%29\"
\n" ); document.write( "cot(30) = tan(60) = \"1%2F%281%2Fsqrt%283%29%29+=+sqrt%283%29\"
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