document.write( "Question 1137343: A rectangular piece of sheet metal has a length that is 4.3 times its width. In each corner a square with sides of 2.1 inches is cut out. The outer strips are then bent up to from an open box with a volume of 265 in^3.
\n" );
document.write( "Find the width (in inches) of the original sheet of metal. \n" );
document.write( "
Algebra.Com's Answer #755217 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! width is x \n" ); document.write( "length is 4.3x \n" ); document.write( "the new width after 2.1 in is cut from each side is x-4.2 and the new length is 4.3x-4.2 \n" ); document.write( "the height is 2.1 in \n" ); document.write( "the volume is 265 in^3 \n" ); document.write( "Therefore, (4.3x^2-18.06x-4.2x+17.64)2.1=265 \n" ); document.write( "or 4.3x^2-18.06x-4.2x+17.64=126.19 \n" ); document.write( "4.3x^2-22.26x-108.55=0 \n" ); document.write( "x=(1/8.6)(22.26+/- sqrt (495.51+1867.06); sqrt=48.61 \n" ); document.write( "=(1/8.6)(22.26+48.61)=8.24 in width ANSWER \n" ); document.write( "length is 35.43 in length \n" ); document.write( "the box is 4.0 in x 31.2 x 2.1 =262.08 in ^3 (rounded) \n" ); document.write( "4.04 in x 31.23 in x 2.1=264.96 in ^3 \n" ); document.write( " \n" ); document.write( " |