document.write( "Question 1137343: A rectangular piece of sheet metal has a length that is 4.3 times its width. In each corner a square with sides of 2.1 inches is cut out. The outer strips are then bent up to from an open box with a volume of 265 in^3.
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Algebra.Com's Answer #755217 by Boreal(15235)\"\" \"About 
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width is x
\n" ); document.write( "length is 4.3x
\n" ); document.write( "the new width after 2.1 in is cut from each side is x-4.2 and the new length is 4.3x-4.2
\n" ); document.write( "the height is 2.1 in
\n" ); document.write( "the volume is 265 in^3
\n" ); document.write( "Therefore, (4.3x^2-18.06x-4.2x+17.64)2.1=265
\n" ); document.write( "or 4.3x^2-18.06x-4.2x+17.64=126.19
\n" ); document.write( "4.3x^2-22.26x-108.55=0
\n" ); document.write( "x=(1/8.6)(22.26+/- sqrt (495.51+1867.06); sqrt=48.61
\n" ); document.write( "=(1/8.6)(22.26+48.61)=8.24 in width ANSWER
\n" ); document.write( "length is 35.43 in length
\n" ); document.write( "the box is 4.0 in x 31.2 x 2.1 =262.08 in ^3 (rounded)
\n" ); document.write( "4.04 in x 31.23 in x 2.1=264.96 in ^3
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