document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=103712>Question 103712</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 39.Twice the first number plus three times the second number is 101. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #75519 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=75519\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x=first, y=second ... x+y=39 ... x=39-y\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "2x+3y=101 ... substituting for x gives 2(39-y)+3y=101 ... 78-2y+3y=101 ... y=23\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x=39-y ... x=39-23 ... x=16 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );