document.write( "Question 103706: hey, how are you? I need help in this problem.\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 3ft more than twice its width, and the area of the rectangle is 35ft. Find the dimensions of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "thanks for your time.\r
\n" ); document.write( "\n" ); document.write( "Juan
\n" ); document.write( "

Algebra.Com's Answer #75518 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
let x=width, so 2x+3=length ... area=x(2x+3) ... 35=2x^2+3x\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2x^2+3x-35=0 ... (2x-7)(x+5)=0 ... x=3.5 and x=-5 ... negative value not realistic
\n" ); document.write( "
\n" );