document.write( "Question 1137268: Find the inverse of matrix of elements cos theta - sin theta
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Algebra.Com's Answer #755152 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Check out this article to see how to find the inverse of a 2x2 matrix. \r
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\n" ); document.write( "\n" ); document.write( "Part of the steps will have us compute the determinant. The determinant of the 2x2 matrix is found through this formula
\n" ); document.write( "E = determinant
\n" ); document.write( "E = a*d - b*c
\n" ); document.write( "where a,b,c,d are arranged like this in the matrix
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\n" ); document.write( "In this case,
\n" ); document.write( "a = cos(theta)
\n" ); document.write( "b = -sin(theta)
\n" ); document.write( "c = sin(theta)
\n" ); document.write( "d = cos(theta)
\n" ); document.write( "which we can see through this comparison
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\n" ); document.write( "\n" ); document.write( "So the determinant is,
\n" ); document.write( "E = a*d - b*c
\n" ); document.write( "E = cos(theta)*cos(theta) - (-sin(theta))*sin(theta)
\n" ); document.write( "E = cos(theta)*cos(theta) + sin(theta)*sin(theta)
\n" ); document.write( "E = cos^2(theta) + sin^2(theta)
\n" ); document.write( "E = 1
\n" ); document.write( "For that last step, you use the pythagorean trig identity. \r
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\n" ); document.write( "\n" ); document.write( "Therefore, the expression \"1%2F%28a%2Ad+-+b%2Ac%29\" is equal to 1 \"1%2F%28a%2Ad+-+b%2Ac%29+=+1%2F1+=+1\", meaning that this portion does not affect the result. This is because multiplying by 1 does not change the answer. We can ignore this piece because the determinant is 1.\r
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\n" ); document.write( "\n" ); document.write( "In that same article I posted, note how the original matrix looks like this
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\n" ); document.write( "and it becomes this
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\n" ); document.write( "You swap a and d; also change the signs of b and c but keep them in the same spot.\r
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\n" ); document.write( "\n" ); document.write( "Since
\n" ); document.write( "a = cos(theta)
\n" ); document.write( "b = -sin(theta)
\n" ); document.write( "c = sin(theta)
\n" ); document.write( "d = cos(theta)
\n" ); document.write( "we can say...
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\n" ); document.write( "which is the inverse of the original matrix. I'll let you confirm this by computing A*B and B*A, where A is the original matrix and B is the inverse matrix. You should get AB = I and BA = I. Recall that the matrix I is the identity matrix.
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