document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1137242>Question 1137242</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Question Help \r<BR>\n" );
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document.write( "A gardener has 37 feet of fencing to be used to enclose a rectangular garden that has a border 2 feet wide surrounding it.\r<BR>\n" );
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document.write( "Use this information to answer the following.\r<BR>\n" );
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document.write( "​(a)  If the length of the garden is to be twice its​ width, what will be the dimensions of the​ garden?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #755098 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=755098\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length= l+4, 2 feet on either side<BR>\n" );
document.write( "width=w+4, same<BR>\n" );
document.write( "but l=2w<BR>\n" );
document.write( "so dimensions are 2w+4+w+4<BR>\n" );
document.write( "the perimeter is twice their sum or 2(3w+8)=6w+16<BR>\n" );
document.write( "6w+16=37<BR>\n" );
document.write( "6w=21<BR>\n" );
document.write( "w=3.5 feet<BR>\n" );
document.write( "length is 7 feet <BR>\n" );
document.write( "width plus fencing is 7.5 feet and length is 11 feet, because both sides have 2 extra feet.<BR>\n" );
document.write( "3.5 x 7 feet answer<BR>\n" );
document.write( "perimeter is 7.5 x 11, with perimeter 37'. </SPAN>\n" );
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