document.write( "Question 1137235: Please help me solve this equation.\r
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document.write( "according to a report by Scarborough Research, the average monthly household cellular phone bill is $73. Supposed monthly household cell phone bills are normally distributed with a standard deviation of $11.\r
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document.write( "a. what is the probability that a randomly selected monthly cell phone bill is less than $95?\r
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document.write( "b. a. what is the probability that a randomly selected monthly cell phone bill is between 62 and $84? \n" );
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Algebra.Com's Answer #755096 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! z=(x-mean)/sd \n" ); document.write( "<(95-73)/11 or <2 \n" ); document.write( "This probability is 0.9772.\r \n" ); document.write( "\n" ); document.write( "Between 62 and 84 is between z=-1 and z=+1 \n" ); document.write( "This has probability 0.6827 \n" ); document.write( " |