document.write( "Question 1137240: Fred has 12 different books
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document.write( "Suppose that Fred first gives three books to Jill and then gives four of the remaining books to Jack how many different outcomes are possible?
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document.write( "Suppose that Fred first gives for books to Jack and then gives three of the remaining books to Jill how many different outcomes are possible?
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document.write( "Explain why the answers to Parts A and B are the same \n" );
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Algebra.Com's Answer #755094 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! the number of ways is 12C3*9C4 \n" ); document.write( "this is 12*11*10/6 multiplied by 9*8*7*6/24\r \n" ); document.write( "\n" ); document.write( "The other way is 12*11*10*9/24 multiplied by 8*7*6/6\r \n" ); document.write( "\n" ); document.write( "If one looks at both numerators and both denominators, it is clear that they are the same.\r \n" ); document.write( "\n" ); document.write( "the answer is 27,720 ways. \n" ); document.write( " |