document.write( "Question 1137195: Kathi and Robert Hawn had a pottery stand at the annual Skippack Craft Fair. They sold some of their pottery at the original price of $ 13.50 each, but later decreased the price of each by $1.00. If they sold all 89 pieces and took in $ 1 comma 133.50, find how many they sold at the original price and how many they sold at the reduced price \n" ); document.write( "

Algebra.Com's Answer #755091 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+x+\"$ = number of pieces sold at original price
\n" ); document.write( " $\"+89+-+x+\"$ = number sold at reduced price
\n" ); document.write( "------------------------------------------------------
\n" ); document.write( " $\"+13.5x+%2B+12.5%2A%28+89+-+x+%29+=+1133.5+\"$
\n" ); document.write( " $\"+13.5x+%2B+1112.5+-+12.5x+=+1133.5+\"$
\n" ); document.write( " $\"+x+=+1133.5+-+1112.5+\"$
\n" ); document.write( " $\"+x+=+21+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+89+-+x+=+68+\"$
\n" ); document.write( "21 sold at original price
\n" ); document.write( "68 sold at reduced price
\n" ); document.write( "-----------------------------------
\n" ); document.write( " $\"+13.5x+%2B+12.5%2A%28+89+-+x+%29+=+1133.5+\"$
\n" ); document.write( " $\"+13.5%2A21+%2B+12.5%2A68+=+1133.5+\"$
\n" ); document.write( " $\"+283.5+%2B+850+=+1133.5+\"$
\n" ); document.write( " $\"+1133.5+=+1133.5+\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

\n" );