document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1137216>Question 1137216</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cube of side length a is modified by cutting a cubic shape of side length b from one of it's corners. In addition a cylindrical hole is cut through the shape with a radius of size c. If the value of a is 18.0, b is 1.2 and c is 5.0, what is the surface area of this shape? (Use 3.14 as the value of pi)\r<BR>\n" );
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document.write( "IMAGE:https://docs.google.com/document/d/1EuzKCVDRH2lBm-0rJ9iJf5z3u57SL8CGyFsLU8AQ7UM/edit?usp=sharing </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #755050 by </B><A HREF=/tutors/aboutme.mpl?userid=MathLover1><B>MathLover1(20849)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathLover1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathLover1><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=755050\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  If the value of <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a+=18.0 ALIGN=MIDDLE  ALT=\"a+=18.0\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b+=1.2+ ALIGN=MIDDLE  ALT=\"b+=1.2+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c+=5.0+ ALIGN=MIDDLE  ALT=\"c+=5.0+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "what is the surface area of this shape? (Use <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3.14 ALIGN=MIDDLE  ALT=\"3.14\"   DISABLED_style= \"max-width:90%; height:auto;\" > as the value of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi ALIGN=MIDDLE  ALT=\"pi\"   DISABLED_style= \"max-width:90%; height:auto;\" >) \r<BR>\n" );
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document.write( " the surface area of this shape will be sum of:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3 ALIGN=MIDDLE  ALT=\"3\"   DISABLED_style= \"max-width:90%; height:auto;\" > faces of the cube side length of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a ALIGN=MIDDLE  ALT=\"a\"   DISABLED_style= \"max-width:90%; height:auto;\" >: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3a%5E2 ALIGN=MIDDLE  ALT=\"3a%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > (these faces have no cuts)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2 ALIGN=MIDDLE  ALT=\"2\"   DISABLED_style= \"max-width:90%; height:auto;\" > faces (upper and one on the left side of big cube) have cut of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E2 ALIGN=MIDDLE  ALT=\"b%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > and area is: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%28a%5E2-b%5E2%29 ALIGN=MIDDLE  ALT=\"2%28a%5E2-b%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1+ ALIGN=MIDDLE  ALT=\"1+\"   DISABLED_style= \"max-width:90%; height:auto;\" >face (front) has a  cut of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E2 ALIGN=MIDDLE  ALT=\"b%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > and circle, so area is: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2-%28b%5E2%2B2c%2Api%29 ALIGN=MIDDLE  ALT=\"a%5E2-%28b%5E2%2B2c%2Api%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "and, add surface area of three faces of small cube side length <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b ALIGN=MIDDLE  ALT=\"b\"   DISABLED_style= \"max-width:90%; height:auto;\" >:<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3b%5E2 ALIGN=MIDDLE  ALT=\"3b%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=surface_+area=3a%5E2%2B2%28a%5E2-b%5E2%29%2Ba%5E2-%28b%5E2%2Bc%5E2%2Api%29%2B3b%5E2 ALIGN=MIDDLE  ALT=\"surface_+area=3a%5E2%2B2%28a%5E2-b%5E2%29%2Ba%5E2-%28b%5E2%2Bc%5E2%2Api%29%2B3b%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=surface_+area=3%2A18%5E2%2B2%2818%5E2-1.2%5E2%29%2B18%5E2-%281.2%5E2%2B25%2A3.14%29%2B3%2A1.44 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=surface_+area=972%2B2%28324-1.44%29%2B324-%281.44%2B78.5%29%2B3%2A1.44 ALIGN=MIDDLE  ALT=\"surface_+area=972%2B2%28324-1.44%29%2B324-%281.44%2B78.5%29%2B3%2A1.44\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=surface_+area=972%2B645.12%2B324-79.94%2B3%2A1.44 ALIGN=MIDDLE  ALT=\"surface_+area=972%2B645.12%2B324-79.94%2B3%2A1.44\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=surface_+area=1865.5 ALIGN=MIDDLE  ALT=\"surface_+area=1865.5\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "or, since we have first deducted <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E2 ALIGN=MIDDLE  ALT=\"b%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > from three faces, then added same as faces of small cube, surface area is same as surface area of cube side length a minus area of the circle\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=surface_+area=++6a%5E2-c%5E2%2Api=6%2A18%5E2-25%2A3.14=1865.5 ALIGN=MIDDLE  ALT=\"surface_+area=++6a%5E2-c%5E2%2Api=6%2A18%5E2-25%2A3.14=1865.5\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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