document.write( "Question 1137199: Joan Arlington has twice as much money invested at 5% simple annual interest as she does at 4%. If her yearly income from the two investments is $364, how much does she have at each rate? \n" ); document.write( "

Algebra.Com's Answer #755039 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "Let x= amount invested at 4%.\r\n" );
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document.write( "Then the total interest equation is\r\n" );
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document.write( "0.05*(2x) + 0.04*x = 364\r\n" );
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document.write( "0.1x + 0.04x = 364\r\n" );
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document.write( "0.14x = 364  ==========>  x =  = 2600.\r\n" );
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document.write( "ANSWER.  $2600 invested at 4%;  Twice of it,  $5200 invested at 5%.\r\n" );
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document.write( "CHECK.   0.04*2600 + 0.05*5200 = $364.   ! Correct !\r\n" );
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