document.write( "Question 1136930: know that in 2006, there is 73% of adults used in internet. a random sample of 120 adults show that there are 95 of them used the internet. use 1% significance level and p-value method to test the claim that the current percentage of canadian adults who now use the internet has increased. \n" ); document.write( "
Algebra.Com's Answer #755031 by Boreal(15235)\"\" \"About 
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will use 1-way
\n" ); document.write( "Ho: use of internet <=0.75
\n" ); document.write( "Ha: use of internet >0.75
\n" ); document.write( "alpha=0.05, p{reject Ho|Ho true)
\n" ); document.write( "test stat 1-sample proportion
\n" ); document.write( "z=(phat-po)/sqrt(p*(1-p)/n)
\n" ); document.write( "reject Ho for z>=2.32
\n" ); document.write( "z=(0.792-0.75)/sqrt (0.75*.25/120)
\n" ); document.write( "z=0.042/0.0395=1.06
\n" ); document.write( "fail to reject Ho at the 1% level
\n" ); document.write( "p-value is z>1.06 or 0.145
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