document.write( "Question 1136930: know that in 2006, there is 73% of adults used in internet. a random sample of 120 adults show that there are 95 of them used the internet. use 1% significance level and p-value method to test the claim that the current percentage of canadian adults who now use the internet has increased. \n" ); document.write( "
Algebra.Com's Answer #755031 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! will use 1-way \n" ); document.write( "Ho: use of internet <=0.75 \n" ); document.write( "Ha: use of internet >0.75 \n" ); document.write( "alpha=0.05, p{reject Ho|Ho true) \n" ); document.write( "test stat 1-sample proportion \n" ); document.write( "z=(phat-po)/sqrt(p*(1-p)/n) \n" ); document.write( "reject Ho for z>=2.32 \n" ); document.write( "z=(0.792-0.75)/sqrt (0.75*.25/120) \n" ); document.write( "z=0.042/0.0395=1.06 \n" ); document.write( "fail to reject Ho at the 1% level \n" ); document.write( "p-value is z>1.06 or 0.145 \n" ); document.write( " \n" ); document.write( " |