document.write( "Question 103836: Sarah is 6 years more than 3 times as old as Denise. In 14 years the sum of thier ages will be 82. How old is Denise now? \n" ); document.write( "

Algebra.Com's Answer #75503 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let S = Sarah's present age and D = Denise's present age.
\n" ); document.write( "From the problem description, you can write:
\n" ); document.write( "1) $\"highlight%28S+=+3D%2B6%29\"$ \"Sarah is 6 years more than 3 times as old as Denise\"
\n" ); document.write( "2) $\"%28highlight%28S%29%2B14%29+%2B+%28D%2B14%29+=+82\"$ \"In 14 years, the sum of their ages will be 82\"
\n" ); document.write( "Substitute the S from equation 1) into equation 2) and solve for D.
\n" ); document.write( "2a) $\"%28highlight%283D%2B6%29%2B14%29+%2B+%28D%2B14%29+=+82\"$ Simplify.
\n" ); document.write( " $\"4D%2B34+=+82\"$ Subtract 34 from both sides.
\n" ); document.write( " $\"4D+=+48\"$ Divide by both sides by 4.
\n" ); document.write( " $\"D+=+12\"$ This is Denise's present age.
\n" ); document.write( " $\"S+=+3D%2B6\"$
\n" ); document.write( " $\"S+=+3%2812%29%2B6\"$
\n" ); document.write( " $\"S+=+36%2B6\"$
\n" ); document.write( " $\"S+=+42\"$ This is Sarah's present age. \n" ); document.write( "

\n" );