document.write( "Question 1137176: The probability that I find defective bulb in a supermarket display is 0.25. Suppose I inspect 16 bulbs, \r
\n" ); document.write( "\n" ); document.write( "a) What is the probability of finding 4 defective bulbs?
\n" ); document.write( "b) What is the probability of finding less than 2 defective bulbs?
\n" ); document.write( "c) How many bulbs do I expect to be defective?
\n" ); document.write( "d) Find the variance of defective bulbs
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Algebra.Com's Answer #755020 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"P%28X%29=C%2816%2CX%29%2A%280.25%29%5EX%2A%281-0.25%29%5E%2816-X%29\"
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\n" ); document.write( "a) \"P%284%29=00.225\"
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\n" ); document.write( "b) Less than 2 would be 0 or 1,
\n" ); document.write( "\"P%28X%3C2%29=P%280%29%2BP%281%29\"
\n" ); document.write( "\"P%28X%3C2%29=0.010%2B0.053\"
\n" ); document.write( "\"P%28x%3C2%29=0.063\"
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\n" ); document.write( "c) Highest probability occurs with \"X=4\".
\n" ); document.write( "From another direction, for a binomial distribution,
\n" ); document.write( "\"mu=n%2AP\"
\n" ); document.write( "\"mu=0.25%2A16\"
\n" ); document.write( "\"mu=4\"
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\n" ); document.write( "d) For a binomial distribution,
\n" ); document.write( "\"sigma=sqrt%28n%2AP%2A%281-P%29%29\"
\n" ); document.write( "\"sigma=sqrt%2816%2A%281%2F4%29%283%2F4%29%29\"
\n" ); document.write( "\"sigma=sqrt%283%29\"
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