document.write( "Question 103836: Sarah is 6 years more than 3 times as old as Denise. In 14 years the sum of thier ages will be 82. How old is Denise now? \n" ); document.write( "

Algebra.Com's Answer #75501 by MathLover1(20850) $\"\"$ $\"About$

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let Sarah's age be $\"x\"$ , and Denise's age be $\"y\"$ .\r
\n" ); document.write( "\n" ); document.write( "given information:
\n" ); document.write( " $\"x+%2B+y+%2B+14+=+82\"$
\n" ); document.write( " $\"x=3y%2B6+\"$ \r
\n" ); document.write( "\n" ); document.write( "so, now substitute $\"x\"$ with $\"3y+%2B+6\"$ and find $\"y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"4y+%2B+14+=+82\"$
\n" ); document.write( " $\"4y+=+82+%96+14\"$
\n" ); document.write( " $\"y+=+68%2F4\"$
\n" ); document.write( " $\"y+=+15.5\"$ Denise is $\"15.5\"$ years old now
\n" ); document.write( " $\"x+=3%2A15.5+%2B+6+=+52.5\"$ and Sarah is $\"52.5\"$ years old now\r
\n" ); document.write( "\n" ); document.write( "in $\"14\"$ years from now the sum of thier ages will be
\n" ); document.write( " $\"52.5+%2B+15.5+%2B+14+=+82\"$
\n" ); document.write( " \n" ); document.write( "

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