document.write( "Question 1137064: An executive invests $25,000, some at 6% and the rest at 5% annual interest. If he receives an annual return of $1,440, how much is invested at each rate? \n" ); document.write( "

Algebra.Com's Answer #754995 by VFBundy(438) $\"\"$ $\"About$

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6% investment:
\n" ); document.write( "Principal = p
\n" ); document.write( "Rate = 0.06
\n" ); document.write( "Interest = 0.06p
\n" ); document.write( "
\n" ); document.write( "5% investment:
\n" ); document.write( "Principal = 25000 - p
\n" ); document.write( "Rate = 0.05
\n" ); document.write( "Interest = 0.05(25000 - p) = 1250 - 0.05p
\n" ); document.write( "
\n" ); document.write( "(0.06p) + (1250 - 0.05p) = 1440
\n" ); document.write( "
\n" ); document.write( "0.01p + 1250 = 1440
\n" ); document.write( "
\n" ); document.write( "0.01p = 190
\n" ); document.write( "
\n" ); document.write( "p = 19000
\n" ); document.write( "
\n" ); document.write( "6% investment:
\n" ); document.write( "Principal = p = $19,000
\n" ); document.write( "
\n" ); document.write( "5% investment:
\n" ); document.write( "Principal = 25000 - p = $6000 \n" ); document.write( "

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