document.write( "Question 103803This question is from textbook beginning and intermediate algebra
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\n" ); document.write( "\n" ); document.write( "x^2 + 1x-20=0
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Algebra.Com's Answer #75499 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:

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\n" ); document.write( " Starting with the general quadratic
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\n" ); document.write( " \"ax%5E2%2Bbx%2Bc=0\"
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\n" ); document.write( " the general solution using the quadratic equation is:
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\n" ); document.write( " \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"
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\n" ); document.write( " So lets solve \"x%5E2%2Bx-20=0\" ( notice \"a=1\", \"b=1\", and \"c=-20\")
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\n" ); document.write( " \"x+=+%28-1+%2B-+sqrt%28+%281%29%5E2-4%2A1%2A-20+%29%29%2F%282%2A1%29\" Plug in a=1, b=1, and c=-20
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\n" ); document.write( " \"x+=+%28-1+%2B-+sqrt%28+1-4%2A1%2A-20+%29%29%2F%282%2A1%29\" Square 1 to get 1
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\n" ); document.write( " \"x+=+%28-1+%2B-+sqrt%28+1%2B80+%29%29%2F%282%2A1%29\" Multiply \"-4%2A-20%2A1\" to get \"80\"
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\n" ); document.write( " \"x+=+%28-1+%2B-+sqrt%28+81+%29%29%2F%282%2A1%29\" Combine like terms in the radicand (everything under the square root)
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\n" ); document.write( " \"x+=+%28-1+%2B-+9%29%2F%282%2A1%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
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\n" ); document.write( " \"x+=+%28-1+%2B-+9%29%2F2\" Multiply 2 and 1 to get 2
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\n" ); document.write( " So now the expression breaks down into two parts
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\n" ); document.write( " \"x+=+%28-1+%2B+9%29%2F2\" or \"x+=+%28-1+-+9%29%2F2\"
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\n" ); document.write( " Lets look at the first part:
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\n" ); document.write( " \"x=%28-1+%2B+9%29%2F2\"
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\n" ); document.write( " \"x=8%2F2\" Add the terms in the numerator
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\n" ); document.write( " \"x=4\" Divide
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\n" ); document.write( " So one answer is
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\n" ); document.write( " \"x=4\"
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\n" ); document.write( " Now lets look at the second part:
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\n" ); document.write( " \"x=%28-1+-+9%29%2F2\"
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\n" ); document.write( " \"x=-10%2F2\" Subtract the terms in the numerator
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\n" ); document.write( " \"x=-5\" Divide
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\n" ); document.write( " So another answer is
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\n" ); document.write( " \"x=-5\"
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\n" ); document.write( " So our solutions are:
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\n" ); document.write( " \"x=4\" or \"x=-5\"
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