document.write( "Question 1137086: Two friends plan to meet at a restaurant for
\n" ); document.write( "lunch. They both leave their homes at 11:30 A.M. and between the two of them, they drive a total of 37.5 mi. Lynn drives in from a neighboring town and averages 15 mph faster than her friend Linda. If they meet at noon, find the average driving speed for each. \n" ); document.write( "
Algebra.Com's Answer #754989 by VFBundy(438)\"\" \"About 
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Linda:
\n" ); document.write( "Distance = d = 0.5r
\n" ); document.write( "Rate = r
\n" ); document.write( "Time = 0.5
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\n" ); document.write( "Lynn:
\n" ); document.write( "Distance = 37.5 - d = 37.5 - 0.5r
\n" ); document.write( "Rate = r + 15
\n" ); document.write( "Time = 0.5
\n" ); document.write( "
\n" ); document.write( "r + 15 = (37.5 - 0.5r)/0.5
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\n" ); document.write( "0.5(r + 15) = 37.5 - 0.5r
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\n" ); document.write( "0.5r + 7.5 = 37.5 - 0.5r
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\n" ); document.write( "r = 30
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\n" ); document.write( "Linda:
\n" ); document.write( "Rate = r = 30 mph
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\n" ); document.write( "Lynn:
\n" ); document.write( "Rate = r + 15 = 45 mph
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