document.write( "Question 1137126: use the intermediate value theorom to determine, if possible whether g(x)=2x^3+3x^2-3x+4 has any real zeroes between -2,-1. show your work \n" ); document.write( "

Algebra.Com's Answer #754967 by Fombitz(32388) $\"\"$ $\"About$

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$\"g%28-2%29=2%28-2%29%5E3%2B3%28-2%29%5E2-3%28-2%29%2B4\"$
\n" ); document.write( " $\"g%28-2%29=2%28-8%29%2B3%284%29-3%28-2%29%2B4\"$
\n" ); document.write( " $\"g%28-2%29=%28-16%29%2B%2812%29%2B%286%29%2B4\"$
\n" ); document.write( " $\"g%28-2%29=6\"$
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\n" ); document.write( " $\"g%28-1%29=2%28-1%29%5E3%2B3%28-1%29%5E2-3%28-1%29%2B4\"$
\n" ); document.write( " $\"g%28-1%29=2%28-1%29%2B3%281%29-3%28-1%29%2B4\"$
\n" ); document.write( " $\"g%28-1%29=%28-2%29%2B%283%29%2B%283%29%2B4\"$
\n" ); document.write( " $\"g%28-1%29=8\"$
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\n" ); document.write( "Since there is no change in sign, the intermediate value theorem can't be used to determine if there a zero in the interval [-2,-1] \n" ); document.write( "

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