document.write( "Question 1137125: A baseball team plays in a stadium that holds 50000 spectators. When the ticket price is $10, the average attendance is 27000. When the price is lowered to $6, the average attendance rose to 39000. \r
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document.write( "Find a demand function, D(q), where q is the quantity or number of spectators and D(q) is linear.\r
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Algebra.Com's Answer #754962 by Theo(13342)![]() ![]() You can put this solution on YOUR website! looks like the demand is based on the price.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you have two points to consider.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let x equal the price and y equal the average attendance.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the two points are (x1,y1) = (10,27000)and (x2,y2) = (6,39000)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the slope of a straight line is equal to (y2-y1) / (x2-x1) = (39000 - 27000) / (6 - 10) which is equal to 12000 / -4 which is equal to -3000.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the slope intercept form of the equation of a straight line is y = mx + b.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "m is the slope and b is the y-intercept.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "replace m with -3000 and the equation becomes y = -3000 * x + b.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to solve for b, replace x and y with the value of one the points on the line.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i chose (6,39000).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = -3000 * x + b becomes 39000 = -3000 * 6 + b\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get 39000 = -18000 + b.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "add 18000 to both sides of this equation to get 39000 + 18000 = b.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for b to get b = 57000.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the equation becomes y = -3000 * x + 57000.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y is the demand and x is the price.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let t = d(x) and the equation becomes d(x) = -3000 * x + 57000.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this can also be shown as d(x) = 57000 - 3000 * x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "based on this equation , .....\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 0, the price is 0 and the demand will be 57000 which will be more than the stadium can hold because the stadium can only hold 50,000.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 6, the price is 6 and the demand is 57000 - 18000 = 39000.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 10, the price is 10 and the demand is 57000 - 30000 = 27000.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |