document.write( "Question 1137117: The sum of two numbers is 17, and twice the larger exceeds three times the smaller by 4. Find the numbers. \n" ); document.write( "

Algebra.Com's Answer #754943 by ikleyn(52803) $\"\"$ $\"About$

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document.write( "Let x be the smaller number.   \r\n" );
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document.write( "Then the larger number is (17-x).\r\n" );
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document.write( "What the condition says about these numbers, is this equality\r\n" );
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document.write( "    2*(17-x) = 3*x + 4.\r\n" );
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document.write( "Simplify and solve this equation\r\n" );
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document.write( "     34 - 2x = 3x + 4\r\n" );
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document.write( "     34 - 4 = 3x + 2x\r\n" );
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document.write( "     30     = 5x    ======>  x =  = 6.\r\n" );
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document.write( "ANSWER.  The smaller number is 6.  The larger number is 17-6 = 11.\r\n" );
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document.write( "CHECK.   Twice the larger is 2*11 = 22;  three times the smaller is 3*6 = 18;  22 - 18 = 4.   ! Correct !\r\n" );
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