document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=103834>Question 103834</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The city is planning to build a small playground on arectangle section of a park. The perimeter of the playground is 80 feet. The two longer sides of the playground will each be 25 feet.<BR>\n" );
document.write( " Now what I did was this..\r<BR>\n" );
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document.write( "80/5= 16 25/5 & 25/5=5+5=10*16=160/5=32ft square.<BR>\n" );
document.write( " But I have a feeling is wrong like I'm missing something I used the L*W operation\r<BR>\n" );
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document.write( "also..\r<BR>\n" );
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document.write( "A rectangle yard is surrounded by a fence that is 26 feet long. The area of the yard is 36 ft square. Determine the dimension of the yard.\r<BR>\n" );
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document.write( "I did this...\r<BR>\n" );
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document.write( "26/2 & 36/2 which gave me<BR>\n" );
document.write( "13   *  18 = 234/2= 117 square feet <BR>\n" );
document.write( "again I used the L*W operation  still I feel is wrong   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #75486 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=75486\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The city is planning to build a small playground on a rectangle section of a park. The perimeter of the playground is 80 feet. The two longer sides of the playground will each be 25 feet.<BR>\n" );
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document.write( "Perimeter = 2*length + 2*width<BR>\n" );
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document.write( "Let the length be 25 ft.; Let the width be \"x\" ft<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "80 = 2*25 + 2x<BR>\n" );
document.write( "30 = 2x<BR>\n" );
document.write( "x = 15<BR>\n" );
document.write( "The width = 15 ft.<BR>\n" );
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document.write( "A rectangle yard is surrounded by a fence that is 26 feet long. The area of the yard is 36 ft square. Determine the dimension of the yard.<BR>\n" );
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document.write( "Formula : Area = length*width<BR>\n" );
document.write( "Perimeter = 2*length + 2*width<BR>\n" );
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document.write( "Let the length by x; let the width by y.\r<BR>\n" );
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document.write( "EQUATIONS:<BR>\n" );
document.write( "xy = 36<BR>\n" );
document.write( "2x+2y=26<BR>\n" );
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document.write( "Simplify:<BR>\n" );
document.write( "y = 36/x<BR>\n" );
document.write( "x+y = 13<BR>\n" );
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document.write( "Substitute y=36/x into x+y=13 to get:<BR>\n" );
document.write( "x+(36/x)= 13<BR>\n" );
document.write( "Multiply thru by x to get:<BR>\n" );
document.write( "x^2 + 36 = 13x<BR>\n" );
document.write( "Rearrange:<BR>\n" );
document.write( "x^2 - 13x + 36 = 0<BR>\n" );
document.write( "Factor:<BR>\n" );
document.write( "(x-4)(x-9)=0<BR>\n" );
document.write( "x = 4 or x=9<BR>\n" );
document.write( "If the width is 4 ft, the length = 36/4 = 9 ft<BR>\n" );
document.write( "If the length is 9 ft.,the width = 36/9 = 4 ft<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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