document.write( "Question 1137008: Hello, the questions is:
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document.write( "A bank pays 12% per annum on its savings accounts. At the end of every three years, a 2% bonus is paid on the balance at that time. Find the annual effective rate of interest earned by an investor if the deposit is withdraw in (a) 3 years (b) 4 years.
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document.write( "I started by noting that j1=12%=.12 and so to find the effective rate I made an equation, letting 1$ accumulate, and tried using .
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document.write( "I am very confused how to integrate the 2% bonus into the problem. \n" );
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Algebra.Com's Answer #754839 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! A bank pays 12% per annum on its savings accounts. \n" ); document.write( " At the end of every three years, a 2% bonus is paid on the balance at that time. Find the annual effective rate of interest earned by an investor if the deposit is withdrawn \n" ); document.write( ": \n" ); document.write( "(a) 3 yrs \n" ); document.write( "Let just use $100 and find the accumulated amt after 3 yrs, \n" ); document.write( " annual, so it's pretty simple \n" ); document.write( "A = 100(1+.12)^3 \n" ); document.write( "A = 100*1.4049 \n" ); document.write( "A = $140.49 \n" ); document.write( "With the 2% bonus: 140.49 * 1.02 = 143.30 \n" ); document.write( ": \n" ); document.write( "Use this to find the effective interest rate (r) \n" ); document.write( "100*(1+r)^3 = 143.30 \n" ); document.write( "(1+r)^3 = 143.30/100 \n" ); document.write( "(1+r)^3 = 1.433 \n" ); document.write( "Using common logs \n" ); document.write( "log((1+r)^3) = log(1.433) \n" ); document.write( "log equiv of exponents. find the log of 1.433 \n" ); document.write( "3*log(1+r) = .156246 \n" ); document.write( "log(1+r) = .156246/3 \n" ); document.write( "log(1+r) = .05208 \n" ); document.write( "Find the antilog of both sides \n" ); document.write( "1 + r = 1.1274 \n" ); document.write( "r = 1.1274 - 1 \n" ); document.write( "r = .1274 or 12.74% is the effective rate after 3 years with the bonus \n" ); document.write( ": \n" ); document.write( "(b) 4 years. Essentially the same procedure \n" ); document.write( "One more year with the accumulate amt of 143.30 at 12% \n" ); document.write( "1.12(143.30) = $160.49 after 4 yrs, find the new r with this amt \n" ); document.write( "100(1+r)^4 = 160.49 \n" ); document.write( "(1+r)^4 = 160.49/100 \n" ); document.write( "log((1+r)^4) = log(1.6049) \n" ); document.write( "log(1+r) = .20544/4 \n" ); document.write( "log(1+r) = .05136 \n" ); document.write( "Antilog \n" ); document.write( "1 + r = 1.1255 \n" ); document.write( "r = .1255 or 12.55% is effective rate after 4 yrs \n" ); document.write( "; \n" ); document.write( "Hey, did this make sense to you, should I have been more step-by-step in the 2nd part? CK \n" ); document.write( " |