document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1136934>Question 1136934</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a triangle, the measures of the first angle is three times the measure of the second angle decreased by 50 degrees. The measure of the third angle is 25 degrees less than second angle. What is the measure of each angle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #754772 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=754772\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let A be the first angle and B be the second angle and C be the third angle.\r<BR>\n" );
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document.write( "A = 3B - 50<BR>\n" );
document.write( "C = B - 25\r<BR>\n" );
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document.write( "A + B + C = 180 becomes 3B - 50 + B + B - 25 = 180\r<BR>\n" );
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document.write( "combine like terms to get 5B - 75 = 180\r<BR>\n" );
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document.write( "add 75 to both sides of the equation to get 5B = 255\r<BR>\n" );
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document.write( "solve for B to get B = 255 / 5 = 51.\r<BR>\n" );
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document.write( "A = 3B - 50 = 3 * 51 - 50 = 153 - 50 = 103\r<BR>\n" );
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document.write( "C = B - 25 = 51 - 25 = 26\r<BR>\n" );
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document.write( "the angles are A = 103 and B = 51 and C = 26\r<BR>\n" );
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document.write( "A + B + C = 103 + 51 + 26 = 180<BR>\n" );
document.write( "103 = 3 * 51 - 50 = 153 - 50 = 103<BR>\n" );
document.write( "26 = 51 - 25 = 26\r<BR>\n" );
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document.write( "all problem statements are confirmed to be satisfied, confirming the solution is good.\r<BR>\n" );
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document.write( "the solution is measure of the first angle is 103 and measure of the second angle is 51 and measure of the third angle is 26.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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