document.write( "Question 1136937: Jenny can run 2 miles per hour more than twice as fast as bob can walk. if bob can walk 3 miles in the same time it takes Jenny to run 7.2 miles, what is bobs walking speed? \n" ); document.write( "

Algebra.Com's Answer #754765 by ikleyn(52832) $\"\"$ $\"About$

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document.write( "J = 2B + 2      (1)    (\"Jenny can run 2 miles per hour more than twice as fast as bob can walk.\")\r\n" );
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document.write( " =         (2)    {The \"time\" equation, literally translated and written as it is given)\r\n" );
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document.write( "From equation (1), substitute the expressin J = 2B + 2 into equation (2). You will get\r\n" );
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document.write( " = .\r\n" );
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document.write( "Cross multiply; then simplify step by step and solve for B :\r\n" );
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document.write( "3*(2B + 2) = 7.2B\r\n" );
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document.write( "6B + 6     = 7.2B\r\n" );
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document.write( "6 = 7.2B - 6B\r\n" );
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document.write( "6 = 1.2B     ===============>  B =  = 5.\r\n" );
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document.write( "Thus Bob walks at the rate 5 miles per hour.\r\n" );
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document.write( "Then Jenny runs at  2B+2 = 2*5 + 2 = 12 miles per hour.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Answered and solved.\r
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\n" ); document.write( "\n" ); document.write( "Notice that the solution and the answer by the other tutor both are wrong.\r
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