document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1136935>Question 1136935</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangular field is 15 Yards less than triple the width. If the perimeter of the field is 346 yards, what are the fields dimensions?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #754755 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=754755\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2L + 2W = 346<BR>\n" );
document.write( "L = 3W - 15 substitute in the equation above<BR>\n" );
document.write( "2(3W - 15) + 2W = 346<BR>\n" );
document.write( "6W - 30 + 2W = 346<BR>\n" );
document.write( "8W = 376<BR>\n" );
document.write( "W = 47<BR>\n" );
document.write( "L = 3W - 15<BR>\n" );
document.write( "L = 3(47) - 15<BR>\n" );
document.write( "L = 126<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "2L + 2W = 346<BR>\n" );
document.write( "2(126) + 2(47) = 346 Correct<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );