document.write( "Question 1136897: The admission fee at an amusement park is $1.25 for children and $4.80 for adults. On a certain day, 234 people entered the park, and the admission fees collected totaled 683 dollars. How many children and how many adults were admitted?
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Algebra.Com's Answer #754732 by rothauserc(4718)\"\" \"About 
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let c be the number of children and a be the number of adults
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\n" ); document.write( "1) a +c = 234
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\n" ); document.write( "2) 4.80a +1.25c = 683
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\n" ); document.write( "solve equation 1 for a
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\n" ); document.write( "a = 234 -c
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\n" ); document.write( "substitute for a in equation 2
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\n" ); document.write( "4.80(234 -c) +1.25c = 683
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\n" ); document.write( "1123.2 -4.80c +1.25c = 683
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\n" ); document.write( "-3.55c = -440.2
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\n" ); document.write( "c = 124
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\n" ); document.write( "a = 234 -124 = 110
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\n" ); document.write( "There are 110 adults and 124 children
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\n" ); document.write( "check answer by substituting for a and c in equation 2
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\n" ); document.write( "4.80(110) +1.25(124) = 683
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\n" ); document.write( "528 +155 = 683
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\n" ); document.write( "683 = 683
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