document.write( "Question 103727: could someone please help me on this equation i am stumped. \"%28x%5E2-36y%5E2%29%2F%287x%5E2-42y%29\"/\"x%5E2%2B6xy\" \n" ); document.write( "
Algebra.Com's Answer #75471 by ursuchacrass(5)\"\" \"About 
You can put this solution on YOUR website!
\"%28x%5E2-36y%5E2%29%2F%287x%5E2-42y%29\"/\"x%5E2%2B6xy\"
\n" ); document.write( "{(x^2-36y^2)/(7x^2-42y)} times 1/x^2+6xy....in dividing a polynomial, the second term, that must be divided, must have its multiplicative inverse or the reciprocal.
\n" ); document.write( "factor the terms....
\n" ); document.write( "(x-6y)(x+6y)/{7(x^2-6y)}{x(x+6y)}
\n" ); document.write( "cancel like terms....
\n" ); document.write( "x-6y/7x^3-42xy
\n" ); document.write( "or
\n" ); document.write( "x-6y/7x(x^2-6y)
\n" ); document.write( "
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