document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1136765>Question 1136765</A>: <I><SPAN STYLE=\"word-break: break-all;\"> To make a 6% acid solution, a chemist mixes some 4% acid solution with 12 L of 10% acid solution. How much of the 4% solution must be added to the 10% solution to make the 6% acid solution?\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "I'm guessing that I need to make x=4% but I'm not sure what I need to use for the other variable. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #754600 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=754600\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is an alternative to the traditional algebraic solution method shown by the other tutor.  If you understand how to use it, it will get you to the answer to any of this kind of mixture problem much faster and with far less effort.<br><BR>\n" );
document.write( "(1) 6% is \"twice as close\" to 4% as it is to 10%.  (6-4=2; 10-6=4)<br><BR>\n" );
document.write( "(2) Therefore, the amount of 4% solution in the mixture must be twice as much as the amount of 10% solution.<br><BR>\n" );
document.write( "(3) Since there are 12L of the 10% solution, you need 24L of the 4% solution. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );