document.write( "Question 1136703: A framed poster has a length of 28 inches and a perimeter of 88 inches. A similar poster has a perimeter of 66 inches. Find the area of the similar poster. \n" ); document.write( "
Algebra.Com's Answer #754516 by ikleyn(52781)\"\" \"About 
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document.write( "If a rectangle has the perimeter of 88 inches and the length of 28 inches, then its width is  \"%2888-2%2A28%29%2F2\" = 16 inches.\r\n" );
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document.write( "Then similar rectangle has \r\n" );
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document.write( "    - the length of  \"28%2A%2866%2F88%29\" = \"28%2A%283%2F4%29\" = 7*3 = 21 inches  and\r\n" );
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document.write( "    - the width  of  \"16%2A%283%2F4%29\" = 12 inches.\r\n" );
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document.write( "The area of the smaller rectangle is  21*12 = 252 square inches.\r\n" );
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