document.write( "Question 1136702: A car travels 200km on a main highway and then travels 30km/h slower on a secondary highway for 160km. The trip took 6 hours in total.
\n" ); document.write( "Set up a rational equation that models this situation and use it to algebraically determine the speed on the main highway.
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Algebra.Com's Answer #754504 by josgarithmetic(39630)\"\" \"About 
You can put this solution on YOUR website!
\"highlight_green%28200%2Fr%2B160%2F%28r-30%29=6%29\"\r
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\n" ); document.write( "\n" ); document.write( "r, car speed on main highway\r
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\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( "r, speed
\n" ); document.write( "x, time
\n" ); document.write( "d, distance
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\n" ); document.write( "\"system%28rx=d%2Cx=d%2Fr%29\"\r
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document.write( "                       SPEEDS        TIMES        DISTANCES\r\n" );
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document.write( "Main hwy               r            200/r          200\r\n" );
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document.write( "Secondary hwy          r-30         160/(r-30)     160\r\n" );
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document.write( "TOTAL                                6\r\n" );
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\n" ); document.write( "Sum of the time quantities totals 6 hours.\r
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\n" ); document.write( "\n" ); document.write( "\"200%2Fr%2B160%2F%28r-30%29=6\"\r
\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( "\"100%2Fr%2B80%2F%28r-30%29=3\"\r
\n" ); document.write( "\n" ); document.write( "\"100%28r-30%29%2B80r=3r%5E2-90r\"\r
\n" ); document.write( "\n" ); document.write( "\"270r-3000=3r%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"90r-1000=r%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"r%5E2-90r%2B1000=0\"\r
\n" ); document.write( "\n" ); document.write( ".\r
\n" ); document.write( "\n" ); document.write( ".
\n" ); document.write( "\"highlight%28r=77%29\"
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