document.write( "Question 1136688: Given that: 8( n+1Cn-1 ) = 5( nC1 )^2. Find the value of n \n" ); document.write( "

Algebra.Com's Answer #754494 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "(n+1)C(n-1) is the same as (n+1)C(2). Then the equation is 8*((n+1)C(2)) = 5*(nC1)^2

\n" ); document.write( " $\"8%28%28n%2B1%29%28n%29%29%2F2+=+5%28n%29%5E2\"$
\n" ); document.write( " $\"8n%28n%2B1%29+=+10n%5E2\"$
\n" ); document.write( " $\"8n%5E2%2B8n+=+10n%5E2\"$
\n" ); document.write( " $\"2n%5E2-8n+=+0\"$
\n" ); document.write( " $\"2n%28n-4%29+=+0\"$

\n" ); document.write( "ANSWER: n=4

\n" ); document.write( "CHECK:
\n" ); document.write( "8*5C3 = 8*5C2 = 8*10 = 80
\n" ); document.write( "5*(4C1)^2 = 5*16 = 80 \n" ); document.write( "

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