document.write( "Question 1136669: Jen Butler has been pricing Speed-Pass train fares for a group trip to New York. Three adults and four children must pay $ 115. Two adults and three children must pay $ 82. Find the price of the adult's ticket and the price of a child's ticket.
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Algebra.Com's Answer #754468 by ikleyn(52790) $\"\"$ $\"About$

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document.write( "3a + 4c = 115    (1)\r\n" );
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document.write( "2a + 3c =  82    (2)\r\n" );
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document.write( "Apply the Elimination method. Multiply eq(1) by 2 (both sides); multiply eq(2) by 3. You will get\r\n" );
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document.write( "6a + 8c = 230    (3)\r\n" );
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document.write( "6a + 9c = 246    (4)\r\n" );
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document.write( "Subtract eq(3) from eq(4).  You will get\r\n" );
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document.write( "     9c - 8c = 246 - 230\r\n" );
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document.write( "      c      = 16.\r\n" );
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document.write( "Substitute c= 16 into eq(2)\r\n" );
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document.write( "     2a + 3*16 = 82\r\n" );
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document.write( "     2a = 82 - 48 = 34  =======>  a = 17.\r\n" );
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document.write( "Answer.  Adult ticket price is $17;  children ticket price is  $16.\r\n" );
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document.write( "CHECK.   3*17 + 4*16 = 115 dollars;  \r\n" );
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document.write( "         2*17 + 3*16 = 82  dollars.    ! Correct !\r\n" );
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