document.write( "Question 1136639: A+b+c+d+e=21
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Algebra.Com's Answer #754434 by ikleyn(52788) $\"\"$ $\"About$

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document.write( "a + b + c + d + e = 21    (1)\r\n" );
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document.write( "a + b = 6                 (2)\r\n" );
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document.write( "b + c = 10                (3)\r\n" );
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document.write( "c + d = 7                 (4)\r\n" );
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document.write( "d + e = 9                 (5)\r\n" );
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document.write( "1.  From equations (2) and (5), substitute  a + b = 6  and   d + e = 9  into equation (1). You will get\r\n" );
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document.write( "    6 + c + 9 = 21,  which implies  c = 21 - 6 - 9 = 6.\r\n" );
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document.write( "2.  Now equation   (3) becomes  b + 6 = 10,  giving  b = 10 - 6 = 4,\r\n" );
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document.write( "    while equation (4) becomes  6 + d =  7,  giving  d =  7 - 6 = 1.\r\n" );
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document.write( "3.  Now equation   (2) becomes  a + 4 = 6,  giving  a = 6 - 4 = 2,\r\n" );
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document.write( "    while equation (5) becomes  1 + e = 9,  giving  e = 9 - 1 = 8.\r\n" );
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document.write( "Answer.  a= 2,  b= 4,  c= 6,  d= 1  and  e= 8.\r\n" );
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