document.write( "Question 1136627: What is the degree and the leading coefficient for x^2 (2x − 3)^2? \n" ); document.write( "
Algebra.Com's Answer #754410 by Theo(13342)\"\" \"About 
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i believe the degree is 4 and the leading coefficient is 4.\r
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\n" ); document.write( "\n" ); document.write( "if you multiply the factors out, you get:\r
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\n" ); document.write( "\n" ); document.write( "x^2 * (2x - 3) * (2x - 3) becomes:\r
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\n" ); document.write( "\n" ); document.write( "(2x^3 - 3x^2) * (2x - 3) which becomes:\r
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\n" ); document.write( "\n" ); document.write( "4x^4 - 6x^3 - 6x^3 + 9x^2 which simplifies to:\r
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\n" ); document.write( "\n" ); document.write( "4x^4 - 12x^3 + 9x^2.\r
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\n" ); document.write( "\n" ); document.write( "since this is already arranged in descending order of degree, then:\r
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\n" ); document.write( "\n" ); document.write( "the degree is 4 and the leading coefficient is 4.\r
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\n" ); document.write( "\n" ); document.write( "the original equation is y = x^2 * (2x-3)^2.\r
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\n" ); document.write( "\n" ); document.write( "the final equation is y = x^4 - 12x^3 + 9x^2.\r
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\n" ); document.write( "\n" ); document.write( "these two equations are equivalent to each other.\r
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\n" ); document.write( "\n" ); document.write( "if you graph them both, they will generate the identical curve, as shown below:\r
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