document.write( "Question 1136607: Let X be a continuous random variable with probability density function Find P(-1 < X < 1). [Hint: You may want to use a CAS to evaluate this.] \n" );
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Algebra.Com's Answer #754391 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! \n" ); document.write( "This function models the normal distribution curve when mu = 0 and sigma = 1, aka this is the standard Z distribution\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The general template is \n" ); document.write( " \n" ); document.write( "Plug in mu = 0 and sigma = 1 to get this slightly simpler equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "which is exactly what you were given to start with. \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Find the area under the curve that is to the left of z = -1.00 using a table such as this one. You should find that P(Z < -1.00) = 0.1587\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Using that same table, you should also find P(Z < 1.00) = 0.8413\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract the areas to get the region between the proper z values we want \n" ); document.write( "P(-1 < Z < 1) = P(Z < 1) - P(Z < -1) \n" ); document.write( "P(-1 < Z < 1) = 0.8413 - 0.1587 \n" ); document.write( "P(-1 < Z < 1) = 0.6826\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 0.6826 (which is approximate) \n" ); document.write( " \n" ); document.write( " |