document.write( "Question 1136607: Let X be a continuous random variable with probability density function \"f%28x%29=%281%2Fsqrt%282pi%29%29e%5E%28-x%5E2%2F2%29\" Find P(-1 < X < 1). [Hint: You may want to use a CAS to evaluate this.] \n" ); document.write( "
Algebra.Com's Answer #754391 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "This function models the normal distribution curve when mu = 0 and sigma = 1, aka this is the standard Z distribution\r
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\n" ); document.write( "\n" ); document.write( "The general template is
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\n" ); document.write( "Plug in mu = 0 and sigma = 1 to get this slightly simpler equation
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\n" ); document.write( "which is exactly what you were given to start with. \r
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\n" ); document.write( "\n" ); document.write( "Find the area under the curve that is to the left of z = -1.00 using a table such as this one. You should find that P(Z < -1.00) = 0.1587\r
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\n" ); document.write( "\n" ); document.write( "Using that same table, you should also find P(Z < 1.00) = 0.8413\r
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\n" ); document.write( "\n" ); document.write( "Subtract the areas to get the region between the proper z values we want
\n" ); document.write( "P(-1 < Z < 1) = P(Z < 1) - P(Z < -1)
\n" ); document.write( "P(-1 < Z < 1) = 0.8413 - 0.1587
\n" ); document.write( "P(-1 < Z < 1) = 0.6826\r
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\n" ); document.write( "\n" ); document.write( "Answer: 0.6826 (which is approximate)
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